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What are the 2 digit numbers that are multiples of 9?
Solutions
- The first ten multiples of 9 are 9, 18, 27, 36, 45, 54, 63, 72, 81, 90.
- For the tens places, note that the number 9 can be thought of as 0 tens and 9 ones so the tens place has a 0.
- We will explain why the digit in the tens place goes up by 1 and the digit in the ones place goes down by 1.
What is the largest multiple of 9?
How to list multiples of a number?
| Multiples of 1 | 1, 2, 3, 4, 5, 6, 7, 8, 9, 10. |
|---|---|
| Multiples of 9 | 9, 18, 27, 36, 45, 54, 63, 72, 81, 90. |
| Multiples of 10 | 10, 20, 30, 40, 50, 60, 70, 80, 90, 100. |
| Multiples of 11 | 11, 22, 33, 44, 55, 66, 77, 88, 99, 110. |
| Multiples of 12 | 12, 24, 36, 48, 60, 72, 84, 96, 108, 120. |
What is the smallest 2 digit multiple of 9?
From Divisibility by 9, the digits of n must add to an integer multiple of 9. But from Sum of Even Integers is Even, the digits of n must add to an even integer multiple of 9: 18,36,54, etc. There is only 1 integer multiple of 9 with 2 digits whose digits add to an even integer multiple of 9, and that is 99.
What is the largest multiple of 9 with three digits?
999
We have found that 108 is the smallest 3-digit number that is divisible by 9. Now we will find the largest 3-digit number that is a multiple of 9. The largest 3 digit number is 999, we can see that 999 is divisible by 9 because it satisfies the divisibility rule for 9.
What is number of factors of 9?
Factors of 9 are 1, 3, and 9. 1 is a universal factor. Factors of a number are the numbers we multiply to get that particular number.
Why do the digits of a multiple of 9 add up to 9?
Not only is the number a multiple of 9, it is 9 times the difference of the two digits. Any such number, when multiplied by 9, has the property that the sum of the digits in the result must be exactly 9.
How many three digit multiples of 9 are there?
eleven three
How many three-digit multiples of 9 consist only of odd digits? giving the six integers 135, 153, 315, 351, 513 and 531. If we do not use a 1, then the only possible integer is 333. Hence there are eleven three-digit multiples of 9 consisting only of odd digits.
What is the largest possible number using all the given digits?
It turns out that because 1 and 2 are small and close together, this minimizes the change if we were to swap them. Naturally, the number 987654321 is the largest possible number using all the given digits. However, it is not divisible by 4. If we switch 1 and 2, we get
How to find the largest multiple of 3 in an array?
Given an array of non-negative integers. Find the largest multiple of 3 that can be formed from array elements. For example, if the input array is {8, 1, 9}, the output should be “9 8 1”, and if the input array is {8, 1, 7, 6, 0}, output should be “8 7 6 0”.
Can a 9 digit number be divisible by 3?
Since the digits add up to 45, which is divisible by 3, this means that if you construct a 9 digit number using all the digits, then that number will be divisible by 3. So we only need to make sure that the number is also divisible by 4.
What are the numbers which are multiple of 3?
This method is based on the following facts about numbers which are multiple of 3. 1) A number is multiple of 3 if and only if the sum of digits of number is multiple of 3. For example, let us consider 8760, it is a multiple of 3 because sum of digits is 8 + 7+ 6+ 0 = 21, which is a multiple of 3.