What is the least number that is divisible by 2 3 4 5 and 7 explain your reasoning?

What is the least number that is divisible by 2 3 4 5 and 7 explain your reasoning?

301 is divisible by 7. Therefore 301 is the least number which leaves remainder as 1 when divided by 2, 3, 4, 5, 6 and leaves no remainder when divided by 7. Option (b) is correct. Note: While taking Least Common Multiple be careful to remove only repeated numbers.

What is the least multiple of 7 which when divided by 2 3 4 5 and 6?

Thus, 117 is the answer. ANSWER : Least multiple of 7, which when divided by 2, 3, 4, 5 and 6 leaves the remainders 1, 2, 3, 4 and 5 is 119.

What is the least number which when divisible by 2 3 4 5 and 6 leaves remainder 1 in each case but when divided by 7 leaves no remainder A 231 B 301 C 371 D 441?

So, the least number is 301 when divided by 2,3,4,5,6 leaves a remainder 1, but when divided by 7, there will be no remainder.

Which of the following is the smallest number that is exactly divisible by 2 3 5 and 7?

Answer: If you mean the Lowest Common Multiple (LCM) then the answer is 30.

What is the least number of 2 3 4 5 and 6?

What I did is given below step wise. Step 1- Find out the LCM of 2, 3, 4, 5, 6 which is 60. Step 2- Add 1 to 60 which is 61. Step 3- Multiple 61 by 7 repeatedly till it fulfills the condition that remainder should be 1.

What is the divisibility rule of 2?

Divisibility Rule for 2 If a number ends in a 0, 2, 4, 6 or 8, it is divisible by 2. All even numbers, by definition, are divisible by 2.

What is the least common multiple of 2 3 4 5 and 6?

60
Answer: LCM of 2, 3, 4, 5, and 6 is 60.

What is the least multiple of 13 which when divided by?

LCM of 4, 5, 6, 7 and 8 = 840. Let require number be 840 K + 2 which is multiple of 13. ∴ Require Number = 840 $latex \times$ 3 + 2 = 2520 + 2 = 2522. Hence option [D] is correct answer.

What is the smallest number divisible by 2 3 4 5 and 6?

The smallest number with four digits that can be divided by 2, 3, 4, 5, 6, and 7 is 1050. The smallest number (LCM) that can be divided by these…

What is the lowest common multiple of 2 3 4 5 6?

We’re looking for a number that is divisible by 2, 3, 4, 5, and 6 (meaning that N is a multiple of those numbers) and that number +1 being divisible by 7. We can make progress on this by seeing that the Lowest Common Multiple of these numbers is 2 × 2 ×3 ×5 = 60.

What is the smallest number divisible by all of the nine numbers?

However, not all numbers are EVENLY divisible by the Nine Numbers. I assume you mean evenly divisible. three factors of 2 (otherwise not divisible by 8). 2 * 2 * 2 * 3 * 3 * 5 * 7 = 2,520. That is, of course, the smallest positive number divisible by all of the Nine Numbers.

What is the 4th digit of a number divisible by 3?

Since all of these candidates end in 2 or 6, the 4th digit can be safely said to be 2 or 6. From our divisibility rules, a number is divisible by 3 if the sum of its digits is divisible by 3. Similarly, a number is divisible by 6 if the sum of its digits is divisible by 3.

How to find the least number divisible by (1…..10) both inclusive?

Find the least number that is divisible by all the numbers between 1 and 10 (both inclusive). we have to take LC M of given numbers. ∴ 2520 is least number divisible by (1…..10) both inclusive.

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