Admin How do you calculate photoelectric kinetic energy?
The maximum kinetic energy of a photoelectron is given by 𝐸 = ℎ 𝑐 𝜆 − 𝑊 , m a x where ℎ is the Planck constant, 𝑐 is the speed of light, 𝜆 is the wavelength of the incident photon, and 𝑊 is the work function of the metal surface.
What is the formula of intensity in photoelectric effect?
According to the photoelectric effect by Planck and Einstein , the kinetic energy of the electrons (Ekin) equals the difference between then photon energy (hν) of the impacting photons and the ionization energy ( J ) of the target ( Ekin= hν – J ).
What is photoelectric effect derive Einstein photoelectric equation?
Hint: Einstein’s photoelectric equation can be derived using the fact that it is based on Planck’s quantum theory. Equate the expression for the energy of the incident photon and maximum kinetic energy of the emitted photon and work function of the metal to get the required expression of Einstein’s photoelectric.
What is the formula of work function in photoelectric effect?
The photoelectric equation involves; h = the Plank constant 6.63 x 10-34 J s. f = the frequency of the incident light in hertz (Hz) φ = the work function in joules (J) Ek = the maximum kinetic energy of the emitted electrons in joules (J)
How do you calculate KEmax?
E = hc / λ KEmax = (hc / λ) – φ You have to remember that v = f = v / λ if you see wavelength on the test. Intensity is a measure of how many photons are incident on the surface in a given amount of time.
How do you calculate stopping potential?
To Find: Stopping potential = Vs =? Given: Initial frequency = ν1 = 2.2 x 1015 Hz, initial stopping potential = Vs1 =6.6 V, Final frequency = ν2 = 4.6 x 1015 Hz, Final stopping potential = Vs2 = 16.5 V, Charge on electron = e = 1.6 x 10-19 C.
How do you calculate kinetic energy gain?
In classical mechanics, kinetic energy (KE) is equal to half of an object’s mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2.