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How do you calculate condensate?
Energy Calculations for Return Condensate
- (hc – hm) = Energy Loss per Pound.
- 44,000 lbs of steam = 44,000 lbs of condensate (90 percent Return) = 39,600 lb.
- 39,600 lb x 157.33 (BTU/lb) = 6,230,268 BTU.
- 6.230268 x $15.30 = $95.32 per hour.
- $95.32 x 8,760 (hours/year) = $835,003.20 per year.
How do you calculate condensate return?
Thus, to calculate the percentage (x) of condensate returned at which the water in the hot well starts boiling, the following formula applies: 100%*4,19 kJ/kg*100 ᵒC = [x%*671 kJ/kg]+[(100-x)%*4,19 kJ/kg*25 ᵒC].
How many pounds of steam does it take to lift a condensate?
This is almost as good as telekinesis. If you remember from high school physics, one pound of pressure will raise water 2.33 feet. Let us assume the condensate pipe is ten feet above the steam trap discharge. If you divide ten feet by 2.33, we would need 4.3 pounds of steam pressure.
How do you calculate steam leaks?
Steam Loss = 22.88 x Pa x D2 Steam flow through a leak can be calculated using a the above orifice equation, which is based on the diameter of the leak, the pressure at the inlet of the orifice, and the pressure at the outlet (atmosphere).
How do you calculate condensate flow from a cooling coil?
If a pound of air takes up 400 gallons of space: 400 x 8.33 = 3332. Divide the answer to Step 1 by the answer to Step 2: 0.078 / 3332 = 2.34 x 10^-5. This answer is the AC’s rate of condensate flow, measured in gallons per minute.
How do you convert steam to condensate?
Latent Heat vs. In steam-using industries, Latent Heat refers to the energy required to transform water into steam, also known as the Enthalpy or Heat of Vaporization. By absorbing this Latent Heat, water becomes steam, and by releasing it, steam reverts to high temperature water (condensate).
How does a condensate return system work?
In a pumped condensate return system, the flashing condensate is discharged into a vented tank, from which the flash steam is removed. The condensate must be pumped from the vented tank to the collecting tank, and then pumped from the collecting tank to the boiler.
How high will a steam trap lift condensate?
Steam Condensate Lift using an On-Off Control Scheme This is enough pressure to lift the condensate 12 feet to a gravity return main.
What temperature is steam at 15 psi?
Saturated Steam Temperatures
| Pressure | Temperature | Temperature |
|---|---|---|
| (p.s.i) | (°F) | (°C) |
| 15 | 249.8 | 121.0 |
| 20 | 258.8 | 126.0 |
| 22 | 261.2 | 127.3 |
How do you calculate steam flow through an orifice?
Steam flow through orifices – for steam pressures ranging 2 – 300 psi
- 1 lb/hr = 1.26×10-4 kg/s.
- 1 psi (lb/in2) = 6,894.8 Pa (N/m2) = 6.895×10-3 N/mm2 = 6.895×10-2 bar.
- convert inch to mm.
How do you calculate steam losses in steam traps?
For the trap in question, assuming a rather modest steam cost of $3 per thousand kg, the loss of steam is estimated to cost: 190/1,000($3) = $0.57/h or $113/wk.
How many Btus does it take to condense water?
When one pound of water boils or evaporates, it absorbs 970 BTU’s at a constant temperature of 212° F. (at sea level) and to condense one pound of steam to water 970 BTU’s must be extracted from it.
How do you calculate the condensate load of a steam condenser?
It can be calculated from the steam flow rate and ratio of flash steam produced by hot water. kg/h. %. kg/h. As a rule of thumb the most extreme condensate load is often double the greatest steam load during operation. It can be calculated from the steam flow rate and ratio of flash steam produced by hot water.
How do you calculate the amount of condensate formed during warm up?
For normal warm up load, the quantity of condensate can be calculated by the following equation: Q = (500 kg) x (100-22) oC x (2.44 kJ/kg o C) x 60 / (2095.73 kJ/kg) x 30 min = 90.58 kg/hr. So, the condensate formed at condition above is 90.58 kg/hr.
How do you calculate kg condensate hour?
Kg Condensate/ Hour = (W * Cp * Temperature rise in ºC)/ (L * t) W = Weight of Material in Kg. Cp = Specific Heat of Material in K Cal./ Kg. º C L = Latent Heat of Steam K Cal./ Kg Same as above except that the Specific Heat of Liquid will apply. Kg Condensate/ Hour = (600 (Wi – Wf) + (Wi * Temperature rise in ºC))/L
What is the formula for calculating latent heat of steam?
L = Latent Heat of Steam K Cal./ Kg Kg Condensate/ Hour = (A * U * Differential Temp. ºC (steam and ambient))/L A = Area of Heating Surface in Sq. Meters U = Heat Transfer Co-eff. K. Cal. / Sq Mt. º C